4 Nov Ch 32 (a Vol). 1. TRANSFORMER! ➣➣➣➣➣ Working Principle of Transformer ➣➣➣➣➣ Transformer Construction. 26 Nov Induction Motor (a Vol. – 2). 1. Electrical Technology Induction Motors Three phase and single phase; 2. Induction Motor: General. B.L. Theraja is the author of A Text Book of Electrical Technology ( avg rating , ratings, 89 reviews, published ), Basic Electronics ( a.
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Calculate the voltage at each load. Find a the current supplied at P and Q and b the power dissipated in the distributor. Hence, drop at the middle point is. Using the previous two equations, we have.
A DC 2-wire feeder supplies a constant load with a sending-end voltage of Bl thareja. It follows from this that the bl thareja voltage drop is the same as that produced by a single load equal to the sum of the various concentrated loads, acting at the centre of gravity of the load system.
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B.L. Theraja (Author of A Text Book of Electrical Technology)
Hence, drop over bl thareja dx is. It may, however, be mentioned here that these days all production of power is as a.
The feeding point Bl thareja is supplied at V and the feeding point B at V and load currents of A and A are taken at points C and D which are metres and metres respectively from the feeding point A. Calculate the currents bl thareja the various. A distributor AB is fed rhareja both ends. It is fed at point A.
electrical book bl thareja, Guides for Electronics. Bharath University
Power connections to the various consumers are given from this distributor and not directly from the feeder. It should be noted that location of point of minimum potential is not affected by the uniformly- bl thareja load of 0. A 3-wire has not only a bl thareja efficiency of transmission Fig.
The way it is done is as follows: Any convenient unit of length may be chosen i. Since points A and B are fed at equal voltages, total drop over the distributor is zero. Let us assume that point of minimum bl thareja M is situated at a distance of x units from P. A circuit-board as tahreja above uses DC current Fig.
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If even this does not goes as it should, we need to start praying! But it is not so in the case of distributors which are tapped off at various places along their entire lengths.
Electrical Power-I ; Bombay Univ. This case can be dealt with either by bl thareja moments in amp-m about the two ends and then tharrja bl thareja guess about the point of minimum potential or by assuming a current x bl thareja at one end and then finding the tyareja current distribution.
Networks — Systems of A. Using the previous two equations, we have Fig. The junction of their armatures is earthed and the neutral wire is taken out from there. Alternative Solution The alternative method is to take the total current fed at one end, say, F 1 as x and then to find the. The cable is uniformly loaded at 0. Hence, their different sections carry different currents thaerja different lengths.
First, consider drop due to concentrated load only. Now, the total drop over PQ should equal bl thareja potential thaeja between ends P and Q i.
Calculate i the point of minimum potential bl thareja the distributor ii the value of minimum potential and iii currents fed at the ends A and B.
Sign up with Google. It is found that 4th point from F 1 is the required point i. The maximum current passing through the conductor should be limited to such a bl thareja as. The standard voltage between the conductors is V. Transmission and Distribution Solution. Calculate the saving in copper bl thareja this voltage thareka doubled with power transmitted remaining the same. For thwreja distributor fed at both ends with equal voltagesbl thareja drop equals zero.
The ends A and B are fed at V.
Let the bl thareja distribution be as shown. On the other hand, d. As yet, there is no economical method of raising the d.
Determine the minimum potential and bl thareja its position. Transmission and Distribution Fig. This can be done bl thareja the help of the following pair of equations: The insulation resistance of the whole system should be bll high so that there is bl thareja undue.
Motors — Objective Tests. M 1 and M 2 are two identical shunt machines coupled mechanically with their armatures and shunt field winding joined in series across the outers. As seen, the potential difference and current have their maximum values at feeding points F 1 and F 2.
Distributor Fed bl thareja Both Ends with Equal Voltages It should be noted that in such cases i the maximum voltage drop must always occur at one of the load points and ii if both feeding ends are at the thafeja potential, then the voltage drop between each end and this point must be the same, which in other words, means that the bl thareja of the moments about ends must be equal.
Two-wire and Three-wire Systems In d. Drop due to uniform load can be found by imagining that the distributor is cut into two at point D so that AD can be looked upon as a distributor fed at one end and loaded uniformly.
The way it is done is as follows:.